Chemistry · 2022
JEE Main · 26 July 2022, Shift 1 · Q87
The amount of charge in F (Faraday) required to obtain one mole of iron from Fe_3 O_4 is \ \ \ \. (Nearest Integer)
The amount of charge in F (Faraday) required to obtain one mole of iron from $\displaystyle \mathrm{Fe}_3 \mathrm{O}_4$ is
\_\_\_\_. (Nearest Integer)
Official answer
3
More from Electrochemistry
- The conductivity of a weak acid HA of concentration 0.001 mol L^-1 is 2.0 × 10^-5 Scm^-1. If Λ_m^°(HA)=190 Scm^2 mol^-1, the ionization constant…2021
- The E^° (volt) values are: Al^3+ / Al,-1.66, Sc^3+ / Sc,-2.08, Fe^3+ / Fe^2+, +0.77, Hg_2^2+ / Hg,+0.79. Arrangement of cations, Al^3+, Sc^3+, Fe^3+…2022
- In which of the following half cells, electrochemical reaction is pH dependent?2022
- At 298 K, a 1 litre solution containing 10 mmol of Cr_2 O_7^2- and 100 mmol of Cr^3+ shows a pH of 3.0. Given: Cr_2 O_7^2- → Cr^3+; E^°=1.330 V and…2023
- The product, which is not obtained during the electrolysis of brine solution is2023
- The solubility product of a sparingly soluble salt A_2 X_3 is 1.1 × 10^-23. If specific conductance of the solution is 3 × 10^-5 S m^-1, the limiting…2022
- The Gibbs energy change (in J) for the given reaction at [Cu^2+]=[Sn^2+]=1 M and 298 K is: Cu( s)+Sn^2+(aq.) → Cu^2+(aq.)+Sn( s); (E_Sn^2+ ∣…2020
- Resistance of a conductivity cell (cell constant 129 m^-1 ) filled with 74.5 ppm solution of KCl is 100 Ω (labelled as solution 1). When the same…2022
JEE Main 2022 Chemistry question, with the answer from NTA’s final answer key. Where our answers come from.