Chemistry · 2016
JEE Main · 9 April 2016, Shift 1 · Q31
The amount of arsenic pentasulphide that can be obtained when 35.5 g arsenic acid is treated with excess H_2 S in the presence of conc. HCl (…
The amount of arsenic pentasulphide that can be obtained when $\displaystyle 35.5$ g arsenic acid is treated with excess $\displaystyle \mathrm{H}_2 \mathrm{~S}$ in the presence of conc. HCl ( assuming $\displaystyle 100$% conversion) is :
Official answer
(3)
0.$\displaystyle 125$ mol
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JEE Main 2016 Chemistry question, with the answer from NTA’s final answer key. Where our answers come from.