Chemistry · 2025
JEE Main · 24 January 2025, Shift 1 · Q72
Standard entropies of X_2, Y_2 and XY_5 are 70,50 and 110 J K^-1 mol^-1 respectively. The temperature in Kelvin at which the reaction 1/2 X_2+5/2 Y_2…
Standard entropies of $\displaystyle \mathrm{X}_2, \mathrm{Y}_2$ and $\displaystyle \mathrm{XY}_5$ are $\displaystyle 70,50$ and $\displaystyle 110 \mathrm{~J} \mathrm{~K}^{-1} \mathrm{~mol}^{-1}$ respectively. The temperature in Kelvin at which the reaction
$$\frac{1}{2} \mathrm{X}_2+\frac{5}{2} \mathrm{Y}_2 \rightleftharpoons \mathrm{XY}_5 \Delta \mathrm{H}^{\Theta}=-35 \mathrm{~kJ} \mathrm{~mol}^{-1}
$$
will be at equilibrium is $\displaystyle \_\_\_\_$ (Nearest integer)
Official answer
From NTA’s final answer key for this paper.
700
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JEE Main 2025 Chemistry question, with the answer from NTA’s final answer key. Where our answers come from.