0.2 %( w / v ) solution of NaOH is measured to have resistivity 870.0 m Ω m. The molar conductivity of the solution will be ____ × 10^2 mS dm^2…

$\displaystyle 0.2 \%(\mathrm{w} / \mathrm{v})$ solution of NaOH is measured to have resistivity $\displaystyle 870.0 \mathrm{~m} \Omega \mathrm{~m}$. The molar conductivity of the solution will be $\displaystyle \_\_\_\_$ $\displaystyle \times 10^2 \mathrm{mS} \mathrm{dm}^2 \mathrm{~mol}^{-1}$. (Nearest integer)