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Chemistry · 2025

JEE Main · 23 January 2025, Shift 1 · Q57

FeO_4^2- → +2.0 V Fe^3+ → 0.8 V Fe^2+ → -0.5 V Fe^0 In the above diagram, the standard electrode potentials are given in volts (over the arrow). The…

$$\mathrm{FeO}_4^{2-} \xrightarrow{+2.0 \mathrm{~V}} \mathrm{Fe}^{3+} \xrightarrow{0.8 \mathrm{~V}} \mathrm{Fe}^{2+} \xrightarrow{-0.5 \mathrm{~V}} \mathrm{Fe}^0 $$ In the above diagram, the standard electrode potentials are given in volts (over the arrow). The value of $\displaystyle \mathrm{E}_{\mathrm{FeO}_4^{2-} / \mathrm{Fe}^{2+}}^{\ominus}$ is
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JEE Main 2025 Chemistry question, with the answer from NTA’s final answer key. Where our answers come from.