Chemistry · 2025
JEE Main · 29 January 2025, Shift 2 · Q54
If C ( diamond ) → C ( graphite )+ X kJ mol^-1; C ( diamond )+ O_2( g ) → CO_2( g )+ Y kJ mol^-1; C ( graphite )+ O_2( g ) → CO_2( g )+ Z kJ mol^-1…
If
$$\begin{aligned}
& \mathrm{C}(\text { diamond }) \rightarrow \mathrm{C}(\text { graphite })+\mathrm{X} \mathrm{~kJ} \mathrm{~mol}^{-1} \\
& \mathrm{C}(\text { diamond })+\mathrm{O}_2(\mathrm{~g}) \rightarrow \mathrm{CO}_2(\mathrm{~g})+\mathrm{Y} \mathrm{~kJ} \mathrm{~mol}^{-1} \\
& \mathrm{C}(\text { graphite })+\mathrm{O}_2(\mathrm{~g}) \rightarrow \mathrm{CO}_2(\mathrm{~g})+\mathrm{Z} \mathrm{~kJ} \mathrm{~mol}^{-1}
\end{aligned}
$$
at constant temperature. Then
Official answer
From NTA’s final answer key for this paper.
(1)
$\displaystyle X=Y-Z$
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JEE Main 2025 Chemistry question, with the answer from NTA’s final answer key. Where our answers come from.