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Chemistry · 2025

JEE Main · 29 January 2025, Shift 2 · Q54

If C ( diamond ) → C ( graphite )+ X kJ mol^-1; C ( diamond )+ O_2( g ) → CO_2( g )+ Y kJ mol^-1; C ( graphite )+ O_2( g ) → CO_2( g )+ Z kJ mol^-1…

If $$\begin{aligned} & \mathrm{C}(\text { diamond }) \rightarrow \mathrm{C}(\text { graphite })+\mathrm{X} \mathrm{~kJ} \mathrm{~mol}^{-1} \\ & \mathrm{C}(\text { diamond })+\mathrm{O}_2(\mathrm{~g}) \rightarrow \mathrm{CO}_2(\mathrm{~g})+\mathrm{Y} \mathrm{~kJ} \mathrm{~mol}^{-1} \\ & \mathrm{C}(\text { graphite })+\mathrm{O}_2(\mathrm{~g}) \rightarrow \mathrm{CO}_2(\mathrm{~g})+\mathrm{Z} \mathrm{~kJ} \mathrm{~mol}^{-1} \end{aligned} $$ at constant temperature. Then
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JEE Main 2025 Chemistry question, with the answer from NTA’s final answer key. Where our answers come from.