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Chemistry · 2019

JEE Main · 12 April 2019, Shift 1 · Q58

Given: Co^3++ e^- → Co^2+; E^°=+1.81 V; Pb^4++2 e^- → Pb^2+; E^°=+1.67 V; Ce^4++ e^- → Ce^3+; E^°=+1.61 V; Bi^3++3 e^- → Bi; E^°=+0.20 V Oxidizing…

Given : $$\begin{aligned} & \mathrm{Co}^{3+}+\mathrm{e}^{-} \rightarrow \mathrm{Co}^{2+} ; \mathrm{E}^{\circ}=+1.81 \mathrm{~V} \\ & \mathrm{~Pb}^{4+}+2 \mathrm{e}^{-} \rightarrow \mathrm{Pb}^{2+} ; \mathrm{E}^{\circ}=+1.67 \mathrm{~V} \\ & \mathrm{Ce}^{4+}+\mathrm{e}^{-} \rightarrow \mathrm{Ce}^{3+} ; \mathrm{E}^{\circ}=+1.61 \mathrm{~V} \\ & \mathrm{Bi}^{3+}+3 \mathrm{e}^{-} \rightarrow \mathrm{Bi} ; \mathrm{E}^{\circ}=+0.20 \mathrm{~V} \end{aligned} $$ Oxidizing power of the species will increase in the order :
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JEE Main 2019 Chemistry question, with the answer from NTA’s final answer key. Where our answers come from.