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Chemistry · 2013
JEE Main 2013 · 2013-04-07 Offline · Q69
Given E_Cr^3+ / Cr^0=-0.74 V; E_MnO_4^- / Mn^2+^0=1.51 V; E_Cr_2 O_7^2- / Cr^3+^0=1.33 V; E_Cl / Cl^-^0=1.36 V Based on the data given above,…
Given
$$\begin{aligned}
& \mathrm{E}_{\mathrm{Cr}^{3+} / \mathrm{Cr}}^0=-0.74 \mathrm{~V} ; \mathrm{E}_{\mathrm{MnO}_4^{-} / \mathrm{Mn}^{2+}}^0=1.51 \mathrm{~V} \\
& \mathrm{E}_{\mathrm{Cr}_2 \mathrm{O}_7^{2-} / \mathrm{Cr}^{3+}}^0=1.33 \mathrm{~V} ; \mathrm{E}_{\mathrm{Cl} / \mathrm{Cl}^{-}}^0=1.36 \mathrm{~V}
\end{aligned}
$$
Based on the data given above, strongest oxidising agent will be :
Official answer
(1)
$\displaystyle \mathrm{MnO}_4^{-}$
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JEE Main 2013 Chemistry question, with the answer from NTA’s final answer key. Where our answers come from.