Electrode potentials ( E^0) are given below: Cu^+ / Cu =+0.52 V, Fe^3+ / Fe^2+=+0.77 V, 1 / 2 I_2( s ) / I^-=+0.54 V, Ag^+ / Ag =+0.88 V. Based on…

Electrode potentials $\displaystyle \left(\mathrm{E}^0\right)$ are given below : $$\begin{aligned} & \mathrm{Cu}^{+} / \mathrm{Cu}=+0.52 \mathrm{~V}, \\ & \mathrm{Fe}^{3+} / \mathrm{Fe}^{2+}=+0.77 \mathrm{~V}, \\ & 1 / 2 \mathrm{I}_2(\mathrm{~s}) / \mathrm{I}^{-}=+0.54 \mathrm{~V}, \\ & \mathrm{Ag}^{+} / \mathrm{Ag}=+0.88 \mathrm{~V} . \end{aligned} $$ Based on the above potentials, strongest oxidizing agent will be :