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Chemistry · 2021

JEE Main · 18 March 2021, Shift 1 · Q56

For the reaction 2 Fe^3+( aq )+2 I^-( aq ) → 2 Fe^2+( aq )+ I_2( s ) the magnitude of the standard molar free energy change, Δ_r G_m^°=- \ \ \ \ kJ…

For the reaction $$2 \mathrm{Fe}^{3+}(\mathrm{aq})+2 \mathrm{I}^{-}(\mathrm{aq}) \rightarrow 2 \mathrm{Fe}^{2+}(\mathrm{aq})+\mathrm{I}_2(\mathrm{~s}) $$ the magnitude of the standard molar free energy change, $\displaystyle \Delta_{\mathrm{r}} \mathrm{G}_{\mathrm{m}}^{\circ}=-$ \_\_\_\_ kJ (Round off to the Nearest Integer). $$\left[\begin{array}{l} \mathrm{E}^{\circ}{ }_{\mathrm{Fe}^{2+} / \mathrm{Fe}(\mathrm{s})}=-0.440 \mathrm{~V} ; \mathrm{E}^{\circ}{ }_{\mathrm{Fe}^{3+} / \mathrm{Fe}(\mathrm{s})}=-0.036 \mathrm{~V} \\ \mathrm{E}^{\circ}{ }_{\mathrm{I}_2 / 2 \mathrm{I}^{-}}=0.539 \mathrm{~V} ; \quad \mathrm{F}=96500 \mathrm{C} \end{array}\right] $$
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JEE Main 2021 Chemistry question, with the answer from NTA’s final answer key. Where our answers come from.