Chemistry · 2026
JEE Main · 23 January 2026, Shift 1 · Q72
For the following gas phase equilibrium reaction at constant temperature, NH_3( g ) ⇌ 1 / 2 N_2( g )+3 / 2 H_2( g ) if the total pressure is √ 3 atm…
For the following gas phase equilibrium reaction at constant temperature,
$$\mathrm{NH}_3(\mathrm{~g}) \rightleftharpoons 1 / 2 \mathrm{~N}_2(\mathrm{~g})+3 / 2 \mathrm{H}_2(\mathrm{~g})
$$
if the total pressure is $\displaystyle \sqrt{3} \mathrm{~atm}$ and the pressure equilibrium constant $\displaystyle \left(K_p\right)$ is $\displaystyle 9$ atm, then the degree of dissociation is given as $\displaystyle \left(x \times 10^{-2}\right)^{-1 / 2}$. The value of $\displaystyle x$ is $\displaystyle \_\_\_\_$. (nearest integer)
Official answer
From NTA’s final answer key for this paper.
125
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JEE Main 2026 Chemistry question, with the answer from NTA’s final answer key. Where our answers come from.