Chemistry · 2026
JEE Main · 4 April 2026, Shift 1 · Q55
At T ( K ), the equilibrium constant of A_2(g)+ B_2(g) ⇌ C (g) is 2.7 × 10^-5. What is the equilibrium constant for 1/3 A_2(g)+1/3 B_2(g) ⇌ 1/3 C (g)…
At $\displaystyle \mathrm{T}(\mathrm{K})$, the equilibrium constant of $\displaystyle \mathrm{A}_2(g)+\mathrm{B}_2(g) \rightleftharpoons \mathrm{C}(g)$ is $\displaystyle 2.7 \times 10^{-5}$. What is the equilibrium constant for $\displaystyle \frac{1}{3} \mathrm{~A}_2(g)+\frac{1}{3} \mathrm{~B}_2(g) \rightleftharpoons \frac{1}{3} \mathrm{C}(g)$ at the same temperature?
Official answer
From NTA’s final answer key for this paper.
(4)
$\displaystyle 3 \times 10^{-2}$
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JEE Main 2026 Chemistry question, with the answer from NTA’s final answer key. Where our answers come from.