Chemistry · 2026
JEE Main · 6 April 2026, Shift 2 · Q74
In a closed flask at 600 K, one mole of X_2 Y_4( g ) attains equilibrium as given below: X_2 Y_4( g ) ⇌ 2 XY_2( g ) At equilibrium, 75 % X_2 Y_4( g )…
In a closed flask at $\displaystyle 600$ K , one mole of $\displaystyle \mathrm{X}_2 \mathrm{Y}_4(\mathrm{~g})$ attains equilibrium as given below :
$$\mathrm{X}_2 \mathrm{Y}_4(\mathrm{~g}) \rightleftharpoons 2 \mathrm{XY}_2(\mathrm{~g})
$$
At equilibrium, $\displaystyle 75 \% \mathrm{X}_2 \mathrm{Y}_4(\mathrm{~g})$ was dissociated and the total pressure is $\displaystyle 1$ atm. The magnitude of $\displaystyle \Delta_{\mathrm{r}} \mathrm{G}^{\ominus}$ (in $\displaystyle \mathrm{kJ} \mathrm{mol}^{-1}$ ) at this temperature is $\displaystyle \_\_\_\_$. (Nearest Integer)
(Given : $\displaystyle \mathrm{R}=8.3 \mathrm{~J} \mathrm{~mol}^{-1} \mathrm{~K}^{-1} ; \ln 10=2.3, \log 2=0.3, \log 3=0.48, \log 5=0.69, \log 7=0.84$ )
Official answer
From NTA’s final answer key for this paper.
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JEE Main 2026 Chemistry question, with the answer from NTA’s final answer key. Where our answers come from.