For the cell Cu ( s )| Cu^2+( aq )(0.1 M ) ∥ Ag^+( aq )(0.01 M )| Ag ( s ) the cell potential E_1=0.3095 V For the cell Cu ( s ) ∣ Cu^2+( aq )(0.01 M…

For the cell $\displaystyle \mathrm{Cu}(\mathrm{s})\left|\mathrm{Cu}^{2+}(\mathrm{aq})(0.1 \mathrm{M}) \| \mathrm{Ag}^{+}(\mathrm{aq})(0.01 \mathrm{M})\right| \mathrm{Ag}(\mathrm{s})$ the cell potential $\displaystyle \mathrm{E}_1=0.3095 \mathrm{~V}$ For the cell $\displaystyle \mathrm{Cu}(\mathrm{s}) \mid \mathrm{Cu}^{2+}(\mathrm{aq})(0.01 \mathrm{M}) \| \mathrm{Ag}^{+}(\mathrm{aq})(0.001 \mathrm{M}) \mid \mathrm{Ag}(\mathrm{s})$ the cell potential = \_\_\_\_ $\displaystyle \times 10^{-2} \mathrm{~V}$. (Round off to the Nearest Integer). [Use : $\displaystyle \frac{2.303 \mathrm{RT}}{\mathrm{F}}=0.059$ ]