Chemistry · 2019
JEE Main · 12 January 2019, Shift 2 · Q58
∧_m^° for NaCl, HCl and NaA are 126.4, 425.9 and 100.5 S cm^2 mol^-1, respectively. If the conductivity of 0.001 M HA is 5 × 10^-5 S cm^-1, degree of…
$\displaystyle \wedge_{\mathrm{m}}^{\circ}$ for $\displaystyle \mathrm{NaCl}, \mathrm{HCl}$ and NaA are $\displaystyle 126.4$, $\displaystyle 425.9$ and $\displaystyle 100.5 \mathrm{~S} \mathrm{~cm}^2 \mathrm{~mol}^{-1}$, respectively. If the conductivity of $\displaystyle 0.001$ M HA is $\displaystyle 5 \times 10^{-5} \mathrm{~S} \mathrm{~cm}^{-1}$, degree of dissociation of HA is :
Official answer
(2)
$\displaystyle 0.125$
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