Chemistry · 2024
JEE Main · 27 January 2024, Shift 2 · Q83
For a certain thermochemical reaction M → N at T =400 K, Δ H^ =77.2 kJ mol^-1, Δ S =122 JK^-1, log equilibrium constant ( log K ) is - ____ × 10^-1.
For a certain thermochemical reaction $\displaystyle \mathrm{M} \rightarrow \mathrm{N}$ at $\displaystyle \mathrm{T}=400 \mathrm{~K}, \Delta \mathrm{H}^{\ominus}=77.2 \mathrm{~kJ} \mathrm{~mol}^{-1}, \Delta \mathrm{~S}=122 \mathrm{JK}^{-1}$, log equilibrium constant $\displaystyle (\log \mathrm{K})$ is - $\displaystyle \_\_\_\_$ $\displaystyle \times 10^{-1}$.
Official answer
From NTA’s final answer key for this paper.
37
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JEE Main 2024 Chemistry question, with the answer from NTA’s final answer key. Where our answers come from.