Consider the following reaction: 3 PbCl_2+2( NH_4)_3 PO_4 → Pb_3( PO_4)_2+6 NH_4 Cl If 72 mmol of PbCl_2 is mixed with 50 mmol of ( NH_4)_3 PO_4,…

Consider the following reaction: $$3 \mathrm{PbCl}_2+2\left(\mathrm{NH}_4\right)_3 \mathrm{PO}_4 \rightarrow \mathrm{~Pb}_3\left(\mathrm{PO}_4\right)_2+6 \mathrm{NH}_4 \mathrm{Cl} $$ If $\displaystyle 72$ mmol of $\displaystyle \mathrm{PbCl}_2$ is mixed with $\displaystyle 50$ mmol of $\displaystyle \left(\mathrm{NH}_4\right)_3 \mathrm{PO}_4$, then the amount of $\displaystyle \mathrm{Pb}_3\left(\mathrm{PO}_4\right)_2$ formed is $\displaystyle \_\_\_\_$ mmol (nearest integer).