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Chemistry · 2024

JEE Main · 4 April 2024, Shift 2 · Q87

From 6.55 g of aniline, the maximum amount of acetanilide that can be prepared will be ____ × 10^-1 g.

From $\displaystyle 6.55$ g of aniline, the maximum amount of acetanilide that can be prepared will be $\displaystyle \_\_\_\_$ $\displaystyle \times 10^{-1} \mathrm{~g}$.
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JEE Main 2024 Chemistry question, with the answer from NTA’s final answer key. Where our answers come from.