Fortification of food with iron is done using FeSO_4.7 H_2 O. The mass in grams of the FeSO_4. 7 H_2 O required to achieve 12 ppm of iron in 150 kg…

Fortification of food with iron is done using $\displaystyle \mathrm{FeSO}_4 .7 \mathrm{H}_2 \mathrm{O}$. The mass in grams of the $\displaystyle \mathrm{FeSO}_4$. $\displaystyle 7 \mathrm{H}_2 \mathrm{O}$ required to achieve $\displaystyle 12$ ppm of iron in $\displaystyle 150$ kg of wheat is $\displaystyle \_\_\_\_$ (Nearest integer) [Given: Molar mass of $\displaystyle \mathrm{Fe}, \mathrm{S}$ and and O respectively are $\displaystyle 56,32$ and $\displaystyle 16 \mathrm{~g} \mathrm{~mol}^{-1}$ ]