Chemistry · 2025
JEE Main · 24 January 2025, Shift 2 · Q56
Based on the data given below: E_Cr_2 O_7^2- / Cr^3+^°=1.33 V, E_Cl_2 / Cl^(-)^°=1.36 V; E_MnO_4^- / Mn^2+^°=1.51 V, E_Cr^3+ / Cr^°=-0.74 V the…
Based on the data given below :
$$\begin{array}{ll}
\mathrm{E}_{\mathrm{Cr}_2 \mathrm{O}_7^{2-} / \mathrm{Cr}^{3+}}^{\circ}=1.33 \mathrm{~V} & \mathrm{E}_{\mathrm{Cl}_2 / \mathrm{Cl}^{(-)}}^{\circ}=1.36 \mathrm{~V} \\
\mathrm{E}_{\mathrm{MnO}_4^{-} / \mathrm{Mn}^{2+}}^{\circ}=1.51 \mathrm{~V} & \mathrm{E}_{\mathrm{Cr}^{3+} / \mathrm{Cr}}^{\circ}=-0.74 \mathrm{~V}
\end{array}
$$
the strongest reducing agent is :
Official answer
From NTA’s final answer key for this paper.
(4)
Cr
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JEE Main 2025 Chemistry question, with the answer from NTA’s final answer key. Where our answers come from.