Chemistry · 2020
JEE Main · 6 September 2020, Shift 2 · Q43
A set of solutions is prepared using 180 g of water as a solvent and 10 g of different non-volatile solutes A, B and C. The relative lowering of…
A set of solutions is prepared using $\displaystyle 180$ g of water as a solvent and $\displaystyle 10$ g of different non-volatile solutes A, B and C. The relative lowering of vapour pressure in the presence of these solutes are in the order [Given, molar mass of $\displaystyle \mathrm{A}=100 \mathrm{~g} \mathrm{~mol}^{-1}$; $\displaystyle \left.\mathrm{B}=200 \mathrm{~g} \mathrm{~mol}^{-1} ; \mathrm{C}=10,000 \mathrm{~g} \mathrm{~mol}^{-1}\right]$
Official answer
(1)
$\displaystyle A>B>C$
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