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Chemistry · 2023

JEE Main · 24 January 2023, Shift 1 · Q51

5 g of NaOH was dissolved in deionized water to prepare a 450 mL stock solution. What volume (in mL) of this solution would be required to prepare…

$\displaystyle 5$ g of NaOH was dissolved in deionized water to prepare a $\displaystyle 450$ mL stock solution. What volume (in mL) of this solution would be required to prepare $\displaystyle 500$ mL of $\displaystyle 0.1$ M solution? $\displaystyle \_\_\_\_$ Given: Molar Mass of $\displaystyle \mathrm{Na}, \mathrm{O}$ and H is $\displaystyle 23$, $\displaystyle 16$ and $\displaystyle 1 \mathrm{~g} \mathrm{~mol}^{-1}$ respectively
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JEE Main 2023 Chemistry question, with the answer from NTA’s final answer key. Where our answers come from.