SolveIt is under development
SolveItJEE Main
Question 59 / 91 · latest first
Chemistry · 2021

JEE Main · 3 August 2021, Shift 1 · Q58

200 mL of 0.85 M acetic acid is shaken with 2 g activated charcoal. The final concentration of the solution after adsorption is 0.75 M. The mass of…

$\displaystyle 200$ mL of $\displaystyle 0.85$ M acetic acid is shaken with $\displaystyle 2$ g activated charcoal. The final concentration of the solution after adsorption is $\displaystyle 0.75$ M . The mass of acetic acid in grams adsorbed per gram of charcoal is equal to \_\_\_\_ $\displaystyle \times 10^{-1}$. (Nearest integer) (Given Atomic mass : $\displaystyle \mathrm{C}=12.0, \mathrm{H}=1.0, \mathrm{O}=16.0 \mathrm{u}$ )
ShareWhatsAppTelegram

More from Surface Chemistry

JEE Main 2021 Chemistry question, with the answer from NTA’s final answer key. Where our answers come from.