In an adsorption isotherm, it is seen that the graph of log (x/m) vs log P, where P is in atm, is a straight line inclined at 45^° and the intercept…

In an adsorption isotherm, it is seen that the graph of $\displaystyle \log \left(\frac{x}{\mathrm{~m}}\right)$ vs $\displaystyle \log \mathrm{P}$, where P is in atm, is a straight line inclined at $\displaystyle 45^{\circ}$ and the intercept is $\displaystyle 0.699$ . The amount of solute in grams adsorbed per gram of adsorbent at a pressure of $\displaystyle 0.5$ atm is $\displaystyle x \times 10^{-3}$. The value of $\displaystyle x$ is \_\_\_\_. (Nearest integer) $\displaystyle \left[\right.$ Use $\displaystyle \left.\log _{10} 2=0.3010 ; \tan 45^{\circ}=1\right]$