1 Faraday electricity was passed through Cu^2+(1.5 M, 1 L ) / Cu and 0.1 Faraday was passed through Ag^+(0.2 M, 1 L ) / Ag electrolytic cells. After…

$\displaystyle 1$ Faraday electricity was passed through $\displaystyle \mathrm{Cu}^{2+}(1.5 \mathrm{M}, 1 \mathrm{~L}) / \mathrm{Cu}$ and $\displaystyle 0.1$ Faraday was passed through $\displaystyle \mathrm{Ag}^{+}(0.2 \mathrm{M}, 1 \mathrm{~L}) / \mathrm{Ag}$ electrolytic cells. After this the two cells were connected as shown below to make an electrochemical cell. The emf of the cell thus formed at $\displaystyle 298$ K is $\displaystyle \_\_\_\_$ mV (nearest integer) Given : $\displaystyle \mathrm{E}_{\mathrm{Cu}^{2+} / \mathrm{Cu}}^{\circ}=0.34 \mathrm{~V}$ $$\mathrm{E}_{\mathrm{Ag}^{+} / \mathrm{Ag}}^{\circ}=0.8 \mathrm{~V} $$ $$\frac{2.303 \mathrm{RT}}{\mathrm{~F}}=0.06 \mathrm{~V} $$