SolveItNCERT · CBSE Boards

CBSE 2025 · Region 5 · Set 1 · Q20 · 2 marks

When a neutron collides with $\displaystyle { }_{92}^{235} \mathrm{U}$, the nucleus gives $\displaystyle { }_{54}^{140} \mathrm{Xe}$ and $\displaystyle { }_{38}^{94} \mathrm{Sr}$ as fission products and two neutrons are ejected. Calculate the mass defect and the energy released (in MeV ) in the process. Given: \[\begin{aligned} & \mathrm{m}\left({ }_{92}^{235} \mathrm{U}\right)=235 \cdot 04393 \mathrm{u}, \quad \mathrm{~m}\left({ }_{54}^{140} \mathrm{Xe}\right)=139 \cdot 92164 \mathrm{u} \\ & \mathrm{~m}\left({ }_{38}^{94} \mathrm{Sr}\right)=93 \cdot 91536 \mathrm{u}, \quad{ }_{0}^{1} \mathrm{n}=1 \cdot 00866 \mathrm{u} \\ & 1 \mathrm{u}=931 \mathrm{MeV} / \mathrm{c}^{2} \end{aligned} \]

NucleiMass-Energy and Nuclear Binding EnergyApplyvery_short_answermedium

More from Nuclei

CBSE Class 12 Physics past-paper question from the 2025board exam, with the answer as CBSE’s own marking scheme gives it. Where our answers come from.