CBSE 2026 · Region 1 · Set 1 · Q8 · 1 mark
The 'distance of closest approach' of an alpha-particle is 'd' when it moves with a velocity $\displaystyle v$ head-on towards the target nucleus. If the velocity of alpha particle is halved, the new 'distance of closest approach' will be -
Official answer
From CBSE’s own marking scheme for this paper.
(D)
4d
AtomsAlpha-particle Scattering and Rutherford’s Nuclear Model of AtomApplymcqmedium
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CBSE Class 12 Physics past-paper question from the 2026board exam, with the answer as CBSE’s own marking scheme gives it. Where our answers come from.