✓ Board-verified
Physics · 2023 · 1 mark
CBSE 2023 · Region 4 · Set 2 · Q9
The difference in mass of ^7 X nucleus and total mass of its constituent nucleons is 21.00 u. The binding energy per nucleon for this nucleus is…
The difference in mass of $\displaystyle { }^{7} \mathrm{X}$ nucleus and total mass of its constituent nucleons is $\displaystyle 21.00$ u . The binding energy per nucleon for this nucleus is equal to the energy equivalent of :
Official answer
(A)
$\displaystyle 3$ u
More from Nuclei
- Calculate the energy released/absorbed in the following nuclear reaction: _6^12 C+_6^12 C →_10^20 Ne+_2^4 He Given: m(_6^12 C)=12 · 000000 u m(_10^20…2024 · asked 2×
- Two nuclei have their mass numbers in the ratio of 8: 1. The ratio of their nuclear densities is:2023
- Briefly explain how energy is produced in stars, giving two examples of the nuclear reactions involved.2025
- A narrow beam of protons, each having 4.1 MeV energy is approaching a sheet of lead (Z=82). Calculate: (i) the speed of a proton in the beam, and…2022
- Explain the terms mass defect and binding energy. How are they related?2026
- Deuterium undergoes the following fusion reaction: _1^2 H+_1^2 H →_2^3 He+_0^1 n+3.27 MeV How long an electric bulb of 200 W will glow by using the…2024
- (i) Prove that the nuclear density is same for all nuclei. (ii) Draw a plot of potential energy of a pair of nucleons as a function of their…2023
- Calculate the binding energy per nucleon (in MeV ) of a helium nucleus ( _2^4 He ). Given: m(_2^4 He)=4 · 002603 u m_n=1.008665 u; m_H=1.007825 u; 1…2025
CBSE Class 12 Physics past-paper question from the 2023 board exam, with the answer as CBSE’s own marking scheme gives it. Where our answers come from.