CBSE 2023 · Region 4 · Set 2 · Q9 · 1 mark
The difference in mass of $\displaystyle { }^{7} \mathrm{X}$ nucleus and total mass of its constituent nucleons is $\displaystyle 21.00$ u . The binding energy per nucleon for this nucleus is equal to the energy equivalent of :
Official answer
From CBSE’s own marking scheme for this paper.
(A)
$\displaystyle 3$ u
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CBSE Class 12 Physics past-paper question from the 2023board exam, with the answer as CBSE’s own marking scheme gives it. Where our answers come from.