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Physics · 2024 · 3 marks
CBSE 2024 · Region 3 · Set 3 · Q26
State Bohr's second postulate for his theory of hydrogen atom. Prove that the radius of Bohr's orbit of a hydrogen atom is directly proportional to…
State Bohr's second postulate for his theory of hydrogen atom. Prove that the radius of Bohr's orbit of a hydrogen atom is directly proportional to $\displaystyle \mathrm{n}^{2}$, where n is the principal quantum number.
Marking-scheme solution
Statement of Bohr's second postulates \(\displaystyle \frac{1}{2}\) Derivation of \(\displaystyle \mathrm{r}_{\mathrm{n}} \alpha \mathrm{n}^{2}\) Bohr's second postulate Electron revolves around the nucleus only in those orbits for which the angular momentum in some integral multiple of \(\displaystyle \mathrm{h} / 2 \pi\). Electrostatic force between revolving electron & nucleus provide requisite centripetal force
\[\frac{m v_{\mathrm{n}}^{2}}{\mathrm{r}_{\mathrm{n}}}=\frac{1}{4 \pi \varepsilon_{0}} \frac{e^{2}}{\mathrm{r}_{\mathrm{n}}^{2}}
\] \(\displaystyle v_{\mathrm{n}}=\frac{e}{\sqrt{4 \pi \varepsilon_{0} m \mathrm{r}_{\mathrm{n}}}}\)
\[m v_{\mathrm{n}} \mathrm{r}_{\mathrm{n}}=\frac{\mathrm{n} \mathrm{h}}{2 \pi}
\] From eqn. (i) and (ii)
\[\mathrm{r}_{\mathrm{n}}=\left(\frac{\mathrm{n}^{2}}{m}\right)\left(\frac{\mathrm{h}}{2 \pi}\right)^{2} \frac{4 \pi \varepsilon_{0}}{e^{2}}
\] \(\displaystyle \mathrm{r}_{\mathrm{n}} \propto \mathrm{n}^{2}\)
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CBSE Class 12 Physics past-paper question from the 2024 board exam, with the answer as CBSE’s own marking scheme gives it. Where our answers come from.