Photoemission of electrons occurs from a metal ( φ 0=1 · 96 eV ) when light of frequency 6.4 × 10^14 Hz is incident on it. Calculate: Energy of a…

(a) Energy of a photon in the incident light: E = hν = (6.626 × 10⁻³⁴ × 6.4 × 10¹⁴) / (1.6 × 10⁻¹⁹) = 2.64 eV (= 42.24 × 10⁻²⁰ J) (b) Maximum kinetic energy: K max = E − φ₀ = 2.64 − 1.96 = 0.68 eV (= 10.88 × 10⁻²⁰ J) (c) Stopping potential: eV₀ = K max ⟹ V₀ = K max / e = 0.68 V.

CBSE 2026 · Region 5 · Set 1 · Q27 · 3 marks

Photoemission of electrons occurs from a metal ( $\displaystyle \phi_{0}=1 \cdot 96 \mathrm{eV}$ ) when light of frequency $\displaystyle 6.4 \times 10^{14} \mathrm{~Hz}$ is incident on it. Calculate:
(a)
Energy of a photon in the incident light,
(b)
The maximum kinetic energy of the emitted electrons, and
(c)
The stopping potential.

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