Light of wavelength 500 nm is incident on caesium metal (work function 2 · 14 eV ) and photoemission of electrons occurs. Calculate the (i) kinetic…

Using Einstein Photoelectric equation \[\begin{aligned} \frac{h c}{\lambda} & =K \cdot E_{\max }+\phi_{0} \\ K \cdot E_{\max } & =\frac{h c}{\lambda}-\phi_{0} \\ & =\frac{1240 \mathrm{eVnm}}{500 \mathrm{~nm}}-2.14 \mathrm{eV} \end{aligned} \] \[\begin{aligned} & K . E_{\max }=0.34 e V \\ & K . E_{\max }=e V_{0} \end{aligned} \] \[\therefore V_{0}=0.34 V \]