CBSE 2024 · Region 2 · Set 3 · Q20 · 2 marks
In Bohr model of hydrogen atom, find the ratio of period of revolution of the electron in the orbit n = $\displaystyle 2$ to that in the orbit n = 1.
Marking-scheme solution
$\displaystyle T=\frac{2 \pi r_{n}}{v_{n}}$
$\displaystyle r_{n} \propto n^{2}$
$\displaystyle v_{n} \propto \frac{1}{n}$
$\displaystyle T \propto n^{3}$
$\displaystyle \frac{T_{2}}{T_{1}}=\frac{\left(n_{2}\right)^{3}}{\left(n_{1}\right)^{3}}$
$\displaystyle =\frac{(2)^{3}}{(1)^{3}}$
$\displaystyle =\frac{8}{1}$
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CBSE Class 12 Physics past-paper question from the 2024board exam, with the answer as CBSE’s own marking scheme gives it. Where our answers come from.