In a fission event of _92^238 U by fast moving neutrons, no neutrons are emitted and final products, after the beta decay of the primary fragments,…

In a fission event of $\displaystyle { }_{92}^{238} \mathrm{U}$ by fast moving neutrons, no neutrons are emitted and final products, after the beta decay of the primary fragments, are $\displaystyle { }_{58}^{140} \mathrm{Ce}$ and $\displaystyle { }_{44}^{99} \mathrm{Ru}$. Calculate Q for this process. Neglect the masses of electrons/ positrons emitted during the intermediate steps. Given : $\displaystyle \mathrm{m}\left({ }_{92}^{238} \mathrm{U}\right)=238.05079 \mathrm{u} ; \mathrm{m}\left({ }_{58}^{140} \mathrm{Ce}\right)=139.90543 \mathrm{u}$ \[\mathrm{m}\left({ }_{44}^{99} \mathrm{Ru}\right)=98.90594 \mathrm{u} ; \mathrm{m}\binom{1}{0}=1.008665 \mathrm{u} \]