Calculate the value of the current passing through the battery in the given circuit diagram.

The given circuit forms a balanced Wheatstone bridge so no current flows through \(\displaystyle 5 \Omega\) resistor. \[\begin{aligned} R_{e q} & =\frac{30 \times 60}{30+60} \\ & =20 \Omega \end{aligned} \] \[\begin{aligned} I & =\frac{V}{R_{e q}} \\ & =\frac{6}{20}=\frac{3}{10} \mathrm{~A} \end{aligned} \]