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Physics · 2026 · 3 marks
CBSE 2026 · Region 4 · Set 2 · Q27
A conducting rectangular loop of area 5 cm^2 and resistance 4 Ω is removed from a region of uniform magnetic field, acting normal to the plane of the…
A conducting rectangular loop of area $\displaystyle 5 \mathrm{~cm}^{2}$ and resistance $\displaystyle 4 \Omega$ is removed from a region of uniform magnetic field, acting normal to the plane of the loop. The value of induced current I in the loop varies with time t, as shown in the figure.
(a)
total charge that passed through the loop
(b)
change in magnetic flux through the loop
(c)
magnitude of magnetic field in the region
Marking-scheme solution
(a)
Q = Area under (I–t) curve
$\displaystyle =\dfrac{1}{2} \times$ base $\displaystyle \times$ height
$\displaystyle =\dfrac{1}{2} \times 0.6 \times 0.3=0.09 \mathrm{C}$
(b)
Change in magnetic flux,
$\displaystyle \Delta \phi=\mathrm{Q} \mathrm{R}$
$\displaystyle =0.09 \times 4$
$\displaystyle =0.36 \mathrm{~Wb}$
(c)
Magnitude of magnetic field
$\displaystyle \mathrm{B}=\dfrac{\Delta \phi}{\mathrm{A}}=\dfrac{0.36}{5 \times 10^{-4}}$
$\displaystyle =720 \mathrm{~T}$
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CBSE Class 12 Physics past-paper question from the 2026 board exam, with the answer as CBSE’s own marking scheme gives it. Where our answers come from.