CBSE 2026 · Region 3 · Set 2 · Q18 · 1 mark
The value of $\displaystyle k$ for which the function $\displaystyle f(x)= \begin{cases}x^{2} \sin \frac{1}{x}, & x \neq 0 \\ k(x+1), & x=0\end{cases}$ is a continuous function, is :
Official answer
From CBSE’s own marking scheme for this paper.
(D)
$\displaystyle 0$
Continuity and DifferentiabilityContinuityApplymcqmedium
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CBSE Class 12 Mathematics past-paper question from the 2026board exam, with the answer as CBSE’s own marking scheme gives it. Where our answers come from.