✓ Board-verified
Mathematics · 2026 · 1 mark
CBSE 2026 · Region 3 · Set 2 · Q18
The value of k for which the function f(x)= {x^2 sin 1/x, x ≠ 0; k(x+1), x=0} is a continuous function, is:
The value of $\displaystyle k$ for which the function $\displaystyle f(x)= \begin{cases}x^{2} \sin \frac{1}{x}, & x \neq 0 \\ k(x+1), & x=0\end{cases}$ is a continuous function, is :
Official answer
(D)
$\displaystyle 0$
All Continuity and Differentiability questions2026 question paperNCERT solutions: Continuity and DifferentiabilityPractice Continuity and Differentiability →
More from Continuity and Differentiability
- The derivative of sin (x^2) w.r.t. x, at x=√π is:2024
- The value of k for which function f(x)= {x^2, x ≥ 0; kx, x<0} is differentiable at x=0 is:2023
- If f(x)= {(sin^2 a x)/(x^2), x ≠ 0; 1, x=0} is continuous at x=0, then the value of a is:2025
- Differentiate y=√(log { sin ((x^3)/3-1)}) with respect to x.2025
- If y=(cos x- sin x)/(cos x+ sin x), then (d y)/(d x) is:2023
- If f(x)= {(log (1+a x)+ log (1-b x))/x, for x ≠ 0; k, for x=0} is continuous at x=0, then the value of k is:2025
- Differentiate sec^-1(1/(√(1-x^2))) w.r.t. sin^-1(2 x √(1-x^2)). OR If y= tan x+ sec x, then prove that (d^2 y)/(d x^2)=(cos x)/((1- sin x)^2).2023
- If f(x)= {(x^2-4 x-5)/(x+1), x ≠-1; k, x=-1} is continuous at x=-1, then the value of k is:2026
CBSE Class 12 Mathematics past-paper question from the 2026 board exam, with the answer as CBSE’s own marking scheme gives it. Where our answers come from.