SolveIt is under development
SolveItNCERT · CBSE · NEET
Question 61 / 122 · latest first
✓ Board-verified
Mathematics · 2024 · 1 mark

CBSE 2024 · Region 2 · Set 1 · Q4

The number of points of discontinuity of f ( x )= {| x |+3, if x ≤-3; -2 x, if -3< x <3; 6 x +2, if x ≥ 3} is:

The number of points of discontinuity of $\displaystyle \mathrm{f}(\mathrm{x})=\left\{\begin{array}{cl}|\mathrm{x}|+3, & \text { if } \mathrm{x} \leq-3 \\ -2 \mathrm{x}, & \text { if }-3<\mathrm{x}<3 \\ 6 \mathrm{x}+2, & \text { if } \mathrm{x} \geq 3\end{array}\right.$ is :
ShareWhatsAppTelegram

More from Continuity and Differentiability

CBSE Class 12 Mathematics past-paper question from the 2024 board exam, with the answer as CBSE’s own marking scheme gives it. Where our answers come from.