Solve the following Linear Programming Problem using graphical method: Maximise Z=100 x+50 y subject to the constraints

Corner Point Value of Z = 100x + 50y --- --- O(0,0) 0 A(0,200) 10000 B(50,250) 17500 C(150,150) 22500 D(200,0) 20000 Z max = 22500 when x = 150, y = 150

CBSE 2025 · Region 4 · Set 1 · Q31 · 3 marks

Solve the following Linear Programming Problem using graphical method : Maximise $\displaystyle \mathrm{Z}=100 \mathrm{x}+50 \mathrm{y}$ subject to the constraints \[\begin{aligned} & 3 \mathrm{x}+\mathrm{y} \leq 600 \\ & \mathrm{x}+\mathrm{y} \leq 300 \\ & \mathrm{y} \leq \mathrm{x}+200 \\ & \mathrm{x} \geq 0, \mathrm{y} \geq 0 \end{aligned} \]

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Corner Point	Value of $\displaystyle Z = 100x + 50y$
$\displaystyle O(0,0)$	$\displaystyle 0$
$\displaystyle A(0,200)$	$\displaystyle 10000$
$\displaystyle B(50,250)$	$\displaystyle 17500$
$\displaystyle C(150,150)$	$\displaystyle 22500$
$\displaystyle D(200,0)$	$\displaystyle 20000$

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