Solve the following Linear Programming Problem graphically: Minimise Z=3 x+5 y subject to the constraints

3 x +5 y <26 has no common region with the feasible region. Z min =26

CBSE 2025 · Region 4 · Set 2 · Q31 · 3 marks

Solve the following Linear Programming Problem graphically : Minimise $\displaystyle \mathrm{Z}=3 \mathrm{x}+5 \mathrm{y}$ subject to the constraints \[\begin{aligned} & \mathrm{x}+2 \mathrm{y} \geq 10 \\ & \mathrm{x}+\mathrm{y} \geq 6 \\ & 3 \mathrm{x}+\mathrm{y} \geq 8 \\ & \mathrm{x}, \mathrm{y} \geq 0 \end{aligned} \]

Linear ProgrammingLinear Programming Problem and its Mathematical FormulationApplyshort_answermedium

Corner Point	Value of $\displaystyle \mathrm{Z}=3 \mathrm{x}+5 \mathrm{y}$
$\displaystyle A(0,8)$	$\displaystyle 40$
$\displaystyle B(1,5)$	$\displaystyle 28$
$\displaystyle C(2,4)$	$\displaystyle 26$
$\displaystyle D(10,0)$	$\displaystyle 30$