CBSE 2026 · Region 2 · Set 1 · Q30 · 3 marks
Solve the following linear programming problem graphically : Maximize $\displaystyle \mathrm{Z}=10500 x+9000 \mathrm{y}$ Subject to constraints \[\begin{aligned} & x+\mathrm{y} \leq 50 \\ & 2 x+\mathrm{y} \leq 80 \\ & x, \mathrm{y} \geq 0 \end{aligned} \]
Marking-scheme solution
| Corner Point | Value of $\displaystyle Z = 10500x + 9000y$ |
| $\displaystyle O(0,0)$ | $\displaystyle 0$ |
| $\displaystyle A(0,50)$ | $\displaystyle 4,50,000$ |
| $\displaystyle B(30,20)$ | $\displaystyle 4,95,000$ |
| $\displaystyle C(40,0)$ | $\displaystyle 4,20,000$ |
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CBSE Class 12 Mathematics past-paper question from the 2026board exam, with the answer as CBSE’s own marking scheme gives it. Where our answers come from.