CBSE 2026 · Region 2 · Set 3 · Q31 · 3 marks
Solve the following linear programming problem graphically: Maximize $\displaystyle \mathrm{Z}=4500 x+5000 \mathrm{y}$ Subject to constraints \[\begin{aligned} & x+\mathrm{y} \leq 250 \\ & 25 x+40 \mathrm{y} \leq 7000 \\ & x \geq 0, \mathrm{y} \geq 0 \end{aligned} \]
Marking-scheme solution
| Corner Point | Value of $\displaystyle Z = 4500x + 5000y$ |
| $\displaystyle O(0,0)$ | $\displaystyle 0$ |
| $\displaystyle A(250,0)$ | $\displaystyle 1125000$ |
| $\displaystyle B(200,50)$ | $\displaystyle 1150000$ |
| $\displaystyle C(0,175)$ | $\displaystyle 875000$ |
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CBSE Class 12 Mathematics past-paper question from the 2026board exam, with the answer as CBSE’s own marking scheme gives it. Where our answers come from.