CBSE 2025 · Region 1 · Set 1 · Q31 · 3 marks
Sketch the graph of $\displaystyle \mathrm{y}=|x+3|$ and find the area of the region enclosed by the curve, $\displaystyle x$-axis, between $\displaystyle x=-6$ and $\displaystyle x=0$, using integration.
Marking-scheme solution
Required Area$\displaystyle = \int_{-6}^{0} y\,dx$$\displaystyle = 2\int_{-3}^{0} (x+3)\,dx$$\displaystyle = 2\left[\dfrac{(x+3)^2}{2}\right]_{-3}^{0}$$\displaystyle = 9$Application of IntegralsArea under Simple CurvesApplyshort_answermedium
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CBSE Class 12 Mathematics past-paper question from the 2025board exam, with the answer as CBSE’s own marking scheme gives it. Where our answers come from.