CBSE 2024 · Region 3 · Set 2 · Q33 · 5 marks
Find the area of the region bounded by the lines $\displaystyle x-2 y=4, x=-1, x=6$ and x -axis, using integration.
Marking-scheme solution
Required area $\displaystyle =\left|\int_{-1}^{4}\left(\frac{x-4}{2}\right) d x\right|+\int_{4}^{6}\left(\frac{x-4}{2}\right) d x$\left.\left.=\left|\frac{(x-4)^{2}}{4}\right|\right]_{-1}^{4}+\frac{(x-4)^{2}}{4}\right]_{4}^{6}
$$
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CBSE Class 12 Mathematics past-paper question from the 2024board exam, with the answer as CBSE’s own marking scheme gives it. Where our answers come from.