CBSE 2025 · Region 5 · Set 1 · Q32 · 5 marks
Sketch a graph of $\displaystyle \mathrm{y}=\mathrm{x}^{2}$. Using integration, find the area of the region bounded by $\displaystyle \mathrm{y}=9, \mathrm{x}=0$ and $\displaystyle \mathrm{y}=\mathrm{x}^{2}$.
Marking-scheme solution
Required area $\displaystyle = \int_0^9 \sqrt{y}\, dy$$\displaystyle = \frac{2}{3}\left[y^{3/2}\right]_0^9$$\displaystyle = 18$Application of IntegralsArea under Simple CurvesApplylong_answermedium
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CBSE Class 12 Mathematics past-paper question from the 2025board exam, with the answer as CBSE’s own marking scheme gives it. Where our answers come from.