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CBSE 2023 · Region 5 · Set 1 · Q2 · 1 mark

$\displaystyle \sin \left[\frac{\pi}{3}+\sin ^{-1}\left(\frac{1}{2}\right)\right]$ is equal to

Inverse Trigonometric FunctionsProperties of Inverse Trigonometric FunctionsApplymcqeasy

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CBSE Class 12 Mathematics past-paper question from the 2023board exam, with the answer as CBSE’s own marking scheme gives it. Where our answers come from.