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CBSE 2023 · Region 2 · Set 1 · Q19 · 1 mark

Assertion (A) : Maximum value of $\displaystyle \left(\cos ^{-1} x\right)^{2}$ is $\displaystyle \pi^{2}$. Reason (R) : Range of the principal value branch of $\displaystyle \cos ^{-1} x$ is $\displaystyle \left[\frac{-\pi}{2}, \frac{\pi}{2}\right]$.

Inverse Trigonometric FunctionsProperties of Inverse Trigonometric FunctionsAnalyseassertion_reasonmedium

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