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Mathematics · 2025 · 1 mark
CBSE 2025 · Region 4 · Set 2 · Q4
If f( x )= {(1- sin^3 x)/(3 cos^2 x), for x ≠ (π)/2; k, for x =(π)/2} is continuous at x =(π)/2, then the value of k is:
If $\displaystyle f(\mathrm{x})=\left\{\begin{array}{cc}\frac{1-\sin ^{3} \mathrm{x}}{3 \cos ^{2} \mathrm{x}}, & \text { for } \mathrm{x} \neq \frac{\pi}{2} \\ k, & \text { for } \mathrm{x}=\frac{\pi}{2}\end{array}\right.$ is continuous at $\displaystyle \mathrm{x}=\frac{\pi}{2}$, then the value of k is :
Official answer
(C)
$\displaystyle \frac{1}{2}$
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CBSE Class 12 Mathematics past-paper question from the 2025 board exam, with the answer as CBSE’s own marking scheme gives it. Where our answers come from.