CBSE 2022 · Region 3 · Set 3 · Q13 · 4 marks
Find the area of the region enclosed by the curves $\displaystyle \mathrm{y}^{2}=x, x=\frac{1}{4}, \mathrm{y}=0$ and $\displaystyle x=1$, using integration. Case Study Problem :
Marking-scheme solution
\[\begin{aligned}
& I=\int_{1 / 4}^{1} \sqrt{x} d x \\
& \left.=\frac{2}{3} x^{3 / 2}\right]_{1 / 4}^{1} \\
& =\frac{2}{3}\left[1-\frac{1}{8}\right]=\frac{7}{12}
\end{aligned}
\]
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CBSE Class 12 Mathematics past-paper question from the 2022board exam, with the answer as CBSE’s own marking scheme gives it. Where our answers come from.