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Mathematics · 2024 · 2 marks
Inverse Trigonometric FunctionsBasic Concepts of Inverse Trigonometric Functions2 marksApplyvery short answer
CBSE 2024 · Region 3 · Set 1 · Q21
Evaluate: sec^2( tan^-1 1/2)+ cosec^2( cot^-1 1/3)
Evaluate : \[\sec ^{2}\left(\tan ^{-1} \frac{1}{2}\right)+\operatorname{cosec}^{2}\left(\cot ^{-1} \frac{1}{3}\right) \]
Marking-scheme solution
$$\begin{aligned}
& \sec ^{2}\left(\tan ^{-1} \frac{1}{2}\right)+\operatorname{cosec}\left(\cot ^{-1} \frac{1}{3}\right) \\
& =\left[1+\tan ^{2}\left(\tan ^{-1} \frac{1}{2}\right)\right]+\left[1+\cot ^{2}\left(\cot ^{-1} \frac{1}{3}\right)\right] \\
& =\left[1+\left(\frac{1}{2}\right)^{2}\right]+\left[1+\left(\frac{1}{3}\right)^{2}\right] \\
& =\frac{85}{36}
\end{aligned}
$$
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CBSE Class 12 Mathematics past-paper question from the 2024 board exam, with the answer as CBSE’s own marking scheme gives it. Where our answers come from.