CBSE 2025 · Region 7 · Set 1 · Q19 · 1 mark
Assertion (A) : $\displaystyle \mathrm{f}(\mathrm{x})=\left\{\begin{array}{c}\mathrm{x} \sin \frac{1}{\mathrm{x}}, \mathrm{x} \neq 0 \\ 0, \mathrm{x}=0\end{array}\right.$ is continuous at $\displaystyle \mathrm{x}=0$. Reason $\displaystyle (R): \quad$ When $\displaystyle \mathrm{x} \rightarrow 0, \sin \frac{1}{\mathrm{x}}$ is a finite value between -$\displaystyle 1$ and $\displaystyle 1$ .
Official answer
From CBSE’s own marking scheme for this paper.
(A)
Both Assertion (A) and Reason (R) are true and Reason (R) is the correct explanation of the Assertion (A).
Continuity and DifferentiabilityContinuityAnalyseassertion_reasonmedium
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CBSE Class 12 Mathematics past-paper question from the 2025board exam, with the answer as CBSE’s own marking scheme gives it. Where our answers come from.